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Guest Message by DevFuse

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722 bad at math


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4 replies to this topic

#1 OFFLINE   DirectFeed

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Posted 11 October 2008 - 07:36 AM

An example of whats happening:

On the DVR, 40 hours of recorded shows (HD). Delete a HD show of two hours in length. Time available on DVR will read something like 41 1/2 hours available.

Doesn't seem the math is good.

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#2 OFFLINE   SaltiDawg

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Posted 11 October 2008 - 08:48 AM

An example of whats happening:

On the DVR, 40 hours of recorded shows (HD). Delete a HD show of two hours in length. Time available on DVR will read something like 41 1/2 hours available.

Doesn't seem the math is good.

Not at all a problem with the math. Depending on the event recorded, memory use required varies all over the place.

In order to estimate hours, the box must make a guess (assumption) as to the nature of what you might choose to record in the future.

#3 OFFLINE   ZBoomer

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Posted 11 October 2008 - 10:00 AM

Exactly, OTA HD requires the most disk space, and closely matches the math the receiver uses.

If you record MPEG2 HD off satellite it uses less, and MPEG4 considerably less even.

#4 OFFLINE   P Smith

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Posted 11 October 2008 - 12:04 PM

The Dish counter rely to unreliable data - compression rate; so don't expect to see exact number.

#5 OFFLINE   DirectFeed

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Posted 11 October 2008 - 12:22 PM

TNX




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